Question

log2(x+1)+log2(x-1)=3

Answer 1

$\log_2(x+1)+\log_2(x-1)=3$
condição x>-1

$\log_2(x+1)(x-1)=3$

$(x+1)(x-1)=2^3$

$x^2-1=8$

$x^{2} =8+1$

$x^{2} =9$

$x= \sqrt{9}$

$x=3$

S= {3}