Question

log2 $\sqrt{32}$=
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Answer 1

Explicação passo-a-passo:

Usando a definição de logaritmo:

$log_{a} =b\\\\a^{x}=b$

$log_{2}\sqrt{32} =x\\\\2^{x}=\sqrt{32} \\\\2^{x}=32^{\frac{1}{2} }\\\\2^{x}=(2^{5})^{\frac{1}{2}} \\ \\2^{x}=2^{\frac{5}{2} }\\\\x=\frac{5}{2} \\\\log_{2}\sqrt{32} =\frac{5}{2}$