Question

Log2  8√64

Log9  3√3

Log2 a=-5

Log1/3 a=4

Log2 0,25

log2 125

 

Answer 1

Log2 8$\sqrt{64}$=x → $2^{x}$=8.8 →$2^{x}$ = 64 → $2^{x}$=$2^{6}$ → x=6

Log9 3$\sqrt{3}$ = x → $9^{x} = 3^{3/2} => 3^{2x} = x^{3/2} => 2x=3/2 x=3/4$

$Log2 a = -5 => a^{-5} = 2 => 1/ a^{5} = 2 => a^{5} = 1/2 => a= \sqrt[5]{1/2} Log1/3 a =4 => (1/3)^{4} = a => 1/81= a Log2 0,25 = x => 2^{x} = 1/4 => 2^{x} = 2^{-2} = > x= -2 Log2 125 = x => 2^{x} = 125 ( Não sei essa )$