Question

Log2(3x+10)-log2x=log2 8

Answer 1

veja....

$\log_2(3x+10)-\log_2x=\log_28 \\ \\ aplicando~~a~~propriedade \\ \\ \log_2 \frac{3x+10}{x} =\log8 \\ \\ \frac{3x+10}{x} =8 \\ \\ 8x=3x+10 \\ 8x-3x=10 \\ 5x=10 \\ x=10\div5 \\ x=2$