Question

log2 1024 = a) log3 243 = b) log5 15625

Answer 1

a)

$\mathsf{log_{2}1024=log_{2^1}2^{32}=\dfrac{32}{1}=32}$

b)

$\mathsf{log_{3}243=log_{3^1}3^5=\dfrac{5}{1}=5}$

c)

$\mathsf{log_{5}15625=log_{5^1}5^6=\dfrac{6}{1}=6}$