Question

log₁₀2 = m e log₁₀3 = n, podemos afirmar que o log₅6 é:

a) 2mn / 1 - m
b) m + n / 1+m
c) 3mn / 1 + m
d) m + n / mn
e) m +n / 1 - m

Answer 1

Explicação passo-a-passo:

$\sf log_{5}~6=\dfrac{log~6}{log~5}$

$\sf log_{5}~6=\dfrac{log~(2\cdot3)}{log~\Big(\frac{10}{2}\Big)}$

$\sf log_{5}~6=\dfrac{log~2+log~3}{log~10-log~2}$

$\sf \red{log_{5}~6=\dfrac{m+n}{1-m}}$

Letra E