Question

log (x2-1) = log (x+1)
Podemos verificar que o valor de x é:

Answer 1

Log (x2-1) = log (x+1)

x2 - 1 = x + 1
x2 - x -1 - 1 = 0
x2 - x - 2 = 0

Δ= (-1)² - 4.1.(-2) = 1+8= 9                        √9 = 3

x = 1+/-3
         2

x1 = 1+3 ==> x1 = 2
         2
x2 = 1-3 ==> x2 = - 1
         2