Question

log x na base 2 + log x-2 na base 2 - log x-3 na base 2= 3

Answer 1

log₂ x + log₂ (x - 2) - log₂ (x - 3) = 3

log₂ [x.(x - 2)/(x - 3)] = 3

$\frac{x.(x-2)}{(x-3)} = 2^{3} =8$

$x.(x-2) = 8.(x-3)$

$x^{2}-2x = 8x-24$

$x^{2}-10x +24=0$

$(x-4).(x-6)=0$

$x=4$  ou  $x=6$

Answer 2

$log_{2}{x}$