Question

log( x+2) + log (x +1)= log 6 são: ​

Answer 1

log( x+2) + log (x +1)= log 6

log ( x+2)•(x +1)= log 6 ==> log morreu!

(x+2)•(x +1)= 6

x²+3x+2= 6

x² +3x -4 = 0 => b/c= 3/-4 = 4-1/4•-1

(x +4). (x -1)= 0

x'=-4. x"=1. => -4 não serve

S: {1 }