Question

log de $\frac{8}{27}$ na base 
\frac{2}{3} [/tex]

Answer 1

$log_{\frac{2}{3}}~\frac{8}{27} = x\\ \\ (\frac{2}{3})^x = \frac{8}{27}\\ \\ (\frac{2}{3})^x=(\frac{2}{3})^3\\ \\ \large\boxed{x=3}}$

Answer 2

Resolução da questão pelos princípios dos logarítmos, veja:


$log_\frac{2}{3}}~\frac{8}{27} = x\\\\\ (\frac{2}{3})^{x} = \frac{8}{27}}\\\\\ (\frac{2}{3})^{x} = (\frac{2}{3})^{3}}\\\\\\\ \large\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{ x = 3.}}}}}}}}}}}}}}}}$

Espero que te ajude. :).