Question

Log de 32 na base x = -5 
Ajuda por favor ?  ;s

Answer 1

$log_{b}(a)=c <=> b^{c}=a$
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$log_{x}(32)=-5$
$x^{-5}=32$
$x^{-5}=2^{5}$
$(x^{-5})^{-1}=(2^{5})^{-1}$
$x^{5}=2^{-5}$
$x^{5}=1/2^{5}$
$x= \sqrt[5]{(1/2^{5})}$
$x=1/2$