Question

log de 2 na base 8 mais log de 4 na base 16. me ajudem.
$log_{8}(2) + log_{16}(4)$
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Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{log_8\:2 + log_{16}\:4}$

$\mathsf{log_{2^3}\:2 + log_{2^4}\:2^2}$

$\mathsf{\dfrac{1}{3}\:log_2\:2 + \dfrac{2}{4}\:log_{2}\:2}$

$\mathsf{\dfrac{1}{3} + \dfrac{2}{4} = \dfrac{4 + 6}{12} = \dfrac{5}{6}}$

$\boxed{\boxed{\mathsf{log_8\:2 + log_{16}\:4 = \left(\dfrac{5}{6}\right)}}}$