Question

log de 0,0625 base 8

Answer 1

$\log_{8} 0,0625=\log_{2^3} \frac{1}{16} =\log_{2^3} 2^{-4}=(-4)\cdot\log_{2^3} 2=(-4)\cdot\frac{1}{3}=-\frac{4}{3}$