Question

Log base 5 logaritmando 3 + log base 5 (x+2)= 2

Answer 1

Resposta:

Explicação passo-a-passo:

$log_53+log_5(x+2)=2\\\\propriedade\\\\loga+logb=log(a.b)\\\\log_53.(x+2)=2\\\\3(x+2)=5^{2}\\ \\3x+6=25\\\\3x=25-6\\\\3x=19\\\\x=\dfrac{19}{3}\\ \\conferindo\\\\log_53.(\dfrac{19}{3}+2)=2\\\\log_53.(\dfrac{19+6}{3})=2\\\\log_53.(\dfrac{25}{3})=2\\\\log_525=2\\\\2=2\\\\OK$