Question

log (4x+3) - log (2x-8) =1​

Answer 1

$log(4x + 3) - log(2x - 8) = log(10)$


então


$log( \frac{4x + 3}{2x - 8} ) = log(10) \\ \\ \frac{4x + 3}{2x - 8} = 10 \\ \\ 4x + 3 = 20x - 80 \\ \\ 16x = 83 \\ \\ x = \frac{83}{16}$