Question

log (3x+23) - log (2x-3)=log4

Answer 1

Temos que:
log(a/b) = loga - logb

log(3x + 23) - log(2x - 3) = log4
log[(3x+ 23) / (2x - 3)] = log4
(3x + 23) / (2x - 3) = 4
4*(2x - 3) = 3x + 23
8x - 12 = 3x + 23
8x - 3x = 23 + 12
5x = 35
x = 35/5
x = 7