Question

log 32 na base raiz quadrada de 2 

Answer 1

Olá, Daiane.

$\log_{\sqrt2}32=\log_{2^\frac12}2^5=5\log_{2^\frac12}2=\frac{5}{\log_{2}2^\frac12}=\\\\ =\frac{5}{\frac12\log_{2}2}=\frac{5}{\frac12\cdot1}=5\cdot2=10$