Question

Log 32 na base 0,25=x

Answer 1

$log_{0,25} 32 = x \\ \\ (0,25)^{x}= 32 \\ \\ (0,25)^{x}=2^{5} \\ \\ ( \frac{1}{4})^{x}=2^{5} \\ \\ (4^{-1})^{x}=2^{5} \\ \\ (2^{2} )^{-1x}=2^{5} \\ \\ 2^{-2x}=2^{5} \\ \\ -2x = 5 \\ \\ x = - \frac{5}{2} = -2,5$

Espero ter ajudado.