Log[³√3]27?????????????
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Definição de logaritmo:
Se
e
, então

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![\log_{\sqrt[3]{3}}\,27=x~\Leftrightarrow~(\sqrt[3]{3})^{x}=27 \log_{\sqrt[3]{3}}\,27=x~\Leftrightarrow~(\sqrt[3]{3})^{x}=27](https://tex.z-dn.net/?f=%5Clog_%7B%5Csqrt%5B3%5D%7B3%7D%7D%5C%2C27%3Dx%7E%5CLeftrightarrow%7E%28%5Csqrt%5B3%5D%7B3%7D%29%5E%7Bx%7D%3D27)
Resolvendo a equação exponencial:
![(\sqrt[3]{3})^{x}=27\\\\(3^{1/3})^{x}=3^{3}\\\\3^{(1/3)\cdot x}=3^{3}\\\\3^{x/3}=3^{3}~~\Leftrightarrow~~\dfrac{x}{3}=3~~\Leftrightarrow~~x=3\cdot3=9 (\sqrt[3]{3})^{x}=27\\\\(3^{1/3})^{x}=3^{3}\\\\3^{(1/3)\cdot x}=3^{3}\\\\3^{x/3}=3^{3}~~\Leftrightarrow~~\dfrac{x}{3}=3~~\Leftrightarrow~~x=3\cdot3=9](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B3%7D%29%5E%7Bx%7D%3D27%5C%5C%5C%5C%283%5E%7B1%2F3%7D%29%5E%7Bx%7D%3D3%5E%7B3%7D%5C%5C%5C%5C3%5E%7B%281%2F3%29%5Ccdot+x%7D%3D3%5E%7B3%7D%5C%5C%5C%5C3%5E%7Bx%2F3%7D%3D3%5E%7B3%7D%7E%7E%5CLeftrightarrow%7E%7E%5Cdfrac%7Bx%7D%7B3%7D%3D3%7E%7E%5CLeftrightarrow%7E%7Ex%3D3%5Ccdot3%3D9)
Portanto,
![\boxed{\boxed{\log_{\sqrt[3]{3}}\,27=9}} \boxed{\boxed{\log_{\sqrt[3]{3}}\,27=9}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Clog_%7B%5Csqrt%5B3%5D%7B3%7D%7D%5C%2C27%3D9%7D%7D)
Se
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Resolvendo a equação exponencial:
Portanto,
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