Question

log 2 (×+2)= log2 (2x-4​

Answer 1

log 2 (×+2)= log2 (2x-4) => log 2 morreu!

(×+2)= (2x-4)

x-2x = -4-2

-x = -6

x = 6

Answer 2

$log_2(x+2) = log_2(2x-4)\\log_2(x+2) - log_2(2x-4) = 0\\log_2(\frac{x+2}{2x-4}) = 0\\\frac{x+2}{2x-4}= 2^0\\\frac{x+2}{2x-4}=1\\x+2 = 2x - 4\\2x - x = 2 + 4\\\boxed{x = 6}$