Question

log 2=0,301 e log 3=0,48 calcule: a)log 8
b)log 72
c)log raiz 2

Answer 1

Boa tarde!!

$a) Log\ 8=Log 2^{3} =3.Log2=3.0,301=0,903 \\ \\ b)Log\ 72=Log 2^{3} . 3^{2} =3.Log\ 2+ 2.Log\ 3=3.0,301+2.0,48=1,863 \\ \\ c)Log \sqrt{2} =Log\ 2^{ \frac{1}{2} } = \frac{1}{2} .Log\ 2= \frac{1}{2} .0,301=0,1505$

Espero ter ajudado <3