Question

Log 16 na base 1/8 = x

Answer 1

$log_{ \frac{1}{8}}16 = x \\ ( \frac{1}{8})^x = 16\\ (\frac{1}{ 2^{3} } )^x = 16 \\ 2^{-3x} = 16 \\ 2^{-3x} = 2^4 \\ -3x = 4 *(-1) \\ 3x = -4 \\ x = \frac{-4}{3}$

Espero ter ajudado ;)