Question

log√12 sabendo q log2=0,3 e log3=0,48

Answer 1

log √12=log √4.3=log 2√3=log 2 +log √3=

log 2 +1/2log 3=0,30 +1/2.0,48=0,30 +0,24===>log √12=0,54

Answer 2

Propriedades de logaritmos:

log√12 = log(12)^(1/2) = 1/2*log12 = 1/2 log(3*2²) = 1/2[log3 + log2²] =

= 1/2[log3 + 2*log2] = 1/2[0,48+ 2*0,3] = 1/2 [0,48 + 0,6] = 1*1,08 = 0,54

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06/09/2016
Sepauto - SSRC
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