Question

Log 1024 - log 0,001 - log 16
2 10 8

Answer 1

$log_21024-log_{10}0,001-log_816=\\ \\ log_22^{10}-log_{10}10^{-3}-log_{2^3}2^4=\\ \\ 10.log_22-(-3).log_{10}10-\frac{3}{4}\\ \\ 10+3-\frac{3}{4}=13-\frac{3}{4}=\frac{51}{4}$