Question

log 10= 1
log2= 0,3010
log3= 0,4471

a) log 32=
b) log 60=
c) log 81=

Answer 1

Resposta:

Explicação passo a passo:

a) log 32=log $2^5$ = 5log2=5*0,3010= 1,505

b) log 60=log(2*3*10) = log2+log3+log10 = 0,3010 + 0,4471 + 1 =1,7481

c) log 81=log $3^4$ = 4*log3=4*0,4471 =1,7884