Question

Log 1 sobre √8 com base ∛4

Answer 1

               $log( \sqrt[3]{4}) \frac{1}{ \sqrt{8} } = y \\ \\ \frac{1}{ \sqrt{8}}= ( \sqrt[3]{4})^y \\ \\ \frac{1}{(2^3) ^{ \frac{1}{2} }} = ((2^2) ^{ \frac{1}{3} } )^y \\ \\ 2^{- \frac{3}{2} }= 2^{ \frac{2y}{3} } \\ \\ - \frac{3}{2}= \frac{2y}{3} \\ \\ -9=4y \\ \\ y=- \frac{9}{4}$