Question

log 1/4 2√2

ajuda please

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}log_{ \frac{1}{4} }\ 2 \sqrt{2} = x \\\\( \frac{1}{4} )^x = 2 \sqrt{2} \\\\(4^{-1})^x = 2 \sqrt{2}\\\\4^{-x} = 2*2^{ \frac{1}{2} }\\\\2^{-2x} = 2^{ \frac{3}{2} } \\\\-2x = \frac{3}{2} \\\\-4x = 3\\\\\boxed{\boxed{x = - \frac{3}{4}}} \end{array}\right$

Espero ter ajudado. :))