Question

log 1/3​ 81=a calcule log16​a2​

Answer 1

Resposta:

$\log_{1\over3}81=a\\ \\ ({1\over3})^{a}=81\\ \\ 3^{-a}=3^4\\ \\ -a=4\\ a=-4\\ \\ ------------\\ \\ \log_{16}a^2=\\ \\ \log_{16}(-4)^2=\log_{16}16=1$