Question

log 1/2 (64 : 128 : 32 ), obtém-se

Answer 1

$log \frac{1}{2} ( \frac{64}{ \frac{128}{32}) }= log \frac{1}{2} + log \frac{64}{ \frac{128}{32}}=log \frac{1}{2} + log \frac{64}{4} = log \frac{1}{2} + log 16 \\ \\ log \frac{1}{2} + log 2^{4}= log \frac{1}{2} + log 2=log 2^{-1} + log 2^{4}= log 2^{-1}.2^{4}= log 2^{3} \\ \\ log 2^{3}=3.log 2= 3.0,30= 0,9$

Espero ter ajudado.