Question

log 1/2 32=x me ajudem pfvrrr ??

Answer 1

$\log_{\frac{1}{2}}32=x\\\\\log_{2^{-1}}2^5=x\\\\\frac{1}{-1}\cdot5\cdot\log_22=\\\\-5\cdot\log_22=\\\\-5\cdot1=\\\\\boxed{-5}$