limites resolver com a resolução.
urgente por favor
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a)
Lim x⁴*(1/x² +2/x)/x⁴(5/x³+3/x⁴-1)
x-->-∞
Lim (1/x² +2/x)/(5/x³+3/x⁴-1) =(0+0)/(0+0-1)=0
x-->-∞
b)
Lim x²/x²(1/x²-5)
x-->-∞
Lim 1/(x²-5) =-1/(0-5) =1/5
x-->-∞
c)
Lim (2 -√(x-3))(2 +√(x-3))/(x-7)*(x+7)(2 +√(x-3))
x-->7
Lim (2² -√(x-3)²)/(x-7)*(x+7)(2 +√(x-3))
x-->7
Lim (4-x+3)/(x-7)*(x+7)(2 +√(x-3)) =
x-->7
Lim (7-x)/(x-7)*(x+7)(2 +√(x-3)) =
x-->7
Lim -1/(x+7)(2 +√(x-3)) = =-1/(14* 4)=-1/56
x-->7
d)
6+==>6 pela direita
Lim 4 /(x-6) =4/0+=+∞
x-->6+
Lim x⁴*(1/x² +2/x)/x⁴(5/x³+3/x⁴-1)
x-->-∞
Lim (1/x² +2/x)/(5/x³+3/x⁴-1) =(0+0)/(0+0-1)=0
x-->-∞
b)
Lim x²/x²(1/x²-5)
x-->-∞
Lim 1/(x²-5) =-1/(0-5) =1/5
x-->-∞
c)
Lim (2 -√(x-3))(2 +√(x-3))/(x-7)*(x+7)(2 +√(x-3))
x-->7
Lim (2² -√(x-3)²)/(x-7)*(x+7)(2 +√(x-3))
x-->7
Lim (4-x+3)/(x-7)*(x+7)(2 +√(x-3)) =
x-->7
Lim (7-x)/(x-7)*(x+7)(2 +√(x-3)) =
x-->7
Lim -1/(x+7)(2 +√(x-3)) = =-1/(14* 4)=-1/56
x-->7
d)
6+==>6 pela direita
Lim 4 /(x-6) =4/0+=+∞
x-->6+
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