Question

Limite x/x-3 x tende a 3

Answer 1

Resposta:

$\lim_{x \to \33} \frac{x}{x-3} = \lim_{x \to \33^{+} } \frac{3}{0^{+} } = + infinito\\\\ \lim_{x \to \33} \frac{x}{x-3} = \lim_{x \to \33^{-} } \frac{3}{0^{-} } = - infinito\\\\Como\: os\:limites\:laterais\:sao\:tistintos,\:esse\:limite\:existe.$

Explicação passo-a-passo: