Question

Limite (x^3 - 27) / (x^2 - 5x + 6). Tende x ->3

Answer 1

x³ -3³ = (x-3).(x²+3x+9)

x² -5x +6 = (x-3).(x-2)

Lim x=>3 (x^3 - 27) / (x^2 - 5x + 6)

Lim x=>3 (x-3).(x²+3x+9) / (x-3).(x-2)

Lim x=>3 (x²+3x+9) / (x-2) =

(9+9+9)/ (1) =

27 ✓