Question

limite tendendo a 3 da raiz quadrada de y-3/y³-27

Answer 1

lim y=>3 √y-3/y³-3³

lim y=>3 √(y-3)/(y-3)(y²+3y+9)

lim y=>3 √1/(y²+3y+9)= √1/27 •(3/3) =

√3/81 = √3 / 9 ✓

bônus da raiz:

√1/27=

√1/√27 •(√3/√3) = √3/√81 = √3 / 9