Question

limite de x tendendo a 6, x+6 / x²-6

Answer 1

$\large\boxed{\begin{array}{l}\displaystyle\sf\lim_{x \to 6}\,\,\dfrac{x+6}{x^2-6}=\dfrac{6+6}{6^2-6}=\dfrac{2\cdot\diagup\!\!\!\!6}{\diagup\!\!\!\!6\cdot(6-1)}\\\\\displaystyle\sf\lim_{x \to 6}\,\,\dfrac{x+6}{x^2-6}=\dfrac{2}{5}\blue{\checkmark}\end{array}}$