Question

limite de (4+t)^2 -16/t , quando t tende a zero.

Answer 1

Boa tarde

f(t) = ((4 + t)^2 -16)/t = (16 + 8t + t² - 16)/t = (t² + 8t)/t = t + 8 

f(t) = t + 8
f(0) = 8