Question

Lim (x³ - 4x + 3) / (x⁵ - 2x + 1)

x→1

Answer 1

Resposta:

$-\dfrac{1}{3}$

Explicação passo-a-passo:

$\lim_{x \to 1} \dfrac{x^3-4x+3}{x^5-2x+1} = \lim_{x \to 1}\dfrac{(x - 1) (x^2 + x - 3)}{(x - 1) (x^4 + x^3 + x^2 + x - 1)}=$

$\lim_{x \to 1}\dfrac{(x^2 + x - 3)}{(x^4 + x^3 + x^2 + x - 1)} = \dfrac{1^2+1-3}{1^4+1^3+1^2+1-1} = -\dfrac{1}{3}$

Answer 2

Resposta:

Explicação passo-a-passo: