Question

lim x2+x-2/x-1 quando x tende a 1

Answer 1

Resposta:

Olá bom dia!

$Lim_{x- > 1} \frac{x^2+x-2}{x-1}$

Observe que o denominador equivale a:

(x + 2) . (x - 1) = (x.x - x + 2x - 2) = (x² + x - 2)

Logo:

$Lim_{x- > 1} \frac{(x+2).(x-1)}{x-1}$

$Lim_{x- > 1} (x+2)$

$= 1 + 2$

= 3