Question

Lim x2+2x+5/x+3 quando x tende a 1​

Answer 1

Vamos là.

lim (x² + 2x + 5)/(x + 3)

x-->1

= (1² + 2*1  + 5)/(1 + 3) = 8/4 = 2

Answer 2

$\Large\displaystyle\text{ \begin{gathered} \sf{ \lim_{x\to1}\frac{x^2+2x+5}{x+3}=\frac{1^2+2\cdot1+5}{1+3}} \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{\lim_{x\to1}\frac{x^2+2x+5}{x+3}=\frac{1+2+5}{4} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{ \lim_{x\to1}\frac{x^2+2x+5}{x+3}=\frac{3+5}{4}} \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered} \sf{\lim_{x\to1}\frac{x^2+2x+5}{x+3}=\frac{8}{4} } \end{gathered} }$

$\Large\displaystyle\text{ \begin{gathered}\red{\underline{\boxed{\boxed{\sf{\lim_{x\to1}\frac{x^2+2x+5}{x+3}=2 }}}}} \end{gathered} }$