Question

lim -x²-2x+3/x²+8x+15
x→ -3

Resposta = 2

Answer 1

Resposta:

Explicação passo-a-passo:

$\lim_{n \to -3}\dfrac{-x^{2}-2x+3}{x^{2}+8x+15}=\lim_{n \to -3}\dfrac{-(x^{2}+2x-3)}{(x+5)(x+3)}=\\\\\\=\lim_{n \to -3}\dfrac{-(x-1)(x+3)}{(x+5)(x+3)}==\lim_{n \to -3}\dfrac{-(x-1)}{(x+5)}=\\\\\\=\dfrac{-(-3-1)}{-3+5}=\dfrac{-(-4)}{2}=\dfrac{4}{2}=2$