Question

lim (x^3-8)/(x^2-4) quando x tende -2

Answer 1

$\lim_{x \to -2} \frac{x^3-8}{x^2-4} = \lim_{x \to -2} \frac{(x+2)(x^2-2x+4)}{(x+2)(x-2)}$

$\lim_{x \to -2} \frac{(x^2-2x+4)}{(x-2)} =\frac{(-2)^2-2(-2)+4)}{(-2-2)} = \frac{12}{(-4)} = -3$