Question

lim [(x-2) (x+4)]
→0

Answer 1

$\lim_{x \to \ 0} (x-2)*(x+4) \\ \\ \lim_{x \to \ 0} x^2 + 2x -8 = \\ \\ \lim_{x \to \ 0} x^2 = 0 \\ \lim_{x \to \ 0} 2x = 0 \\ \lim_{x \to \ 0} -8 = -8$

Então 

$\lim_{x \to \ 0} (x-2)*(x+4) = -8$