Question

lim x^2+3x-10/x^2-x-6,x=2

Answer 1

$\boxed{ \lim_{x \to 2} \frac{x^2+3x-10}{x^2-x-6} = \lim_{x \to 2} \frac{(x+5)(x-2)}{(x+2)(x-3)} =\frac{0}{-4}=0}$