Question

lim X→2 =( √(2x²-3x+2)-2)/(√(3x²-5x+1)-1)

Answer 1

só substituir direto 

$\lim_{x \to 2} \frac{ \sqrt{2x^2-3x+2}-2 }{ \sqrt{3x^2-5x+1}-1 }= \frac{ \sqrt{2(2)^2-3(2)+2}-2 }{ \sqrt{3(2)^2-5(2)+1}-1 }= \frac{ \sqrt{4}-2 }{ \sqrt{3}-1 }= \frac{0}{ \sqrt{3}-1}=0$