Question

lim ∞ x^2 - 16 / x^2 +4

Answer 1

Lim{x→∞} (x² - 16) / (x² +4) =

Lim{x→∞} (x²)/x² - 16/x²) / (x²/x² + 4/x²) =

Lim{x→∞} (1 - 16/x²) / (1 + 4/x²) =

Passando o limite fica:

(1 - 0)/(1-0) = 1/1 = 1

∴ Lim{x→∞} (x² - 16) / (x² +4) = 1 

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16/10/2016
Sepauto
SSRC
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Answer 2

Olá Marcos

lim -->∞ (x² - 16)/(x² + 4) = x²/x² = 1

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