Question

Lim->4 (x³+3x²+2x-5/2x²+9x+2)

Answer 1

$\lim_{x \to 4} \frac{x^3 + 3x^2 + 2x - 5}{2x^2 + 9x + 2}$

$\frac{4^3 + 3*(4)^2 + 2 * 4 - 5}{2 * (4)^2 + 9 * 4 + 2} = \frac{64 + 48 + 8 - 5}{32 + 36 + 2} = \frac{115}{70} = \frac{23}{14}$