Question

lim >-3    x² +2x-3 / 5-3x

Answer 1

$\lim_{x \to -3} \frac{x^2+2x-3}{5-3x} \\ \\ \lim_{x \to -3} \frac{(-3)^2+2(-3)-3}{5-3(-3)} \\ \\ \lim_{x \to -3} \frac{9-6-3}{5+9} \\ \\ \lim_{x \to -3} \frac{0}{14} \\ \\ \lim_{x \to -3} 0 \\ \\ Portanto \\ \\ \lim_{x \to -3} \frac{x^2+2x-3}{5-3x} =0$

Answer 2

Resposta:

Basta substituir x= -3 na função dada.