Question

lim de x tendendo a 0 x (x^2-1)/x^2

Answer 1

$\displaystyle \lim_{x\to 0}\frac{x^2-1}{x^2}\implies \lim_{x\to 0}\frac{\frac{x^2}{x^2}\frac{-1}{x^2}}{\frac{x^2}{x^2}}=\lim_{x\to 0}\frac{1-\frac{1}{x^2}}{1}\imples\\\\ \lim_{x\to 0}1-\frac{1}{x^2}=1-\infty=-\infty$