Question

lim 4x-8 / x^2-5x+6 sendo (x=2)

Answer 1

$\lim_{x \to \22} \frac{4x-8}{x^2-5x+6} = \lim_{x \to \22} \frac{4(x-2)}{(x-2)(x-3)} = \lim_{x \to \22} \frac{4}{x-3} = \frac{4}{2-3} = \frac{4}{-1} =-4$