Question

lim 2x+3
_______
(x-1)²

o limite tende a x ->1

Answer 1

$\lim_{x \to \ 1} \frac{2x+3}{(x-1)^2}= (\lim_{x \to 1} 2x+3).( \lim_{x \to 1} \frac{1}{(x-1)^2}})=5.\infty=\infty$